for x> 0 and y> 0 > . how do I find out whats equivalent to the square root of 16x^9 y^36?

My answer is 4y^18x^4 square root x

Is that correct? I think I did something wrong

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- Jan 9th 2013, 08:13 AMtahirakwSquare root
for x> 0 and y> 0 > . how do I find out whats equivalent to the square root of 16x^9 y^36?

My answer is 4y^18x^4 square root x

Is that correct? I think I did something wrong - Jan 9th 2013, 08:19 AMPlatoRe: Square root
- Jan 9th 2013, 08:25 AMtahirakwRe: Square root
Thanks