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Math Help - boolean algebra simplify

  1. #1
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    boolean algebra simplify

    need help with simplifing ab'c(bd+cde)+ac'. book answer indicates a(c'+b'de) i get a(c'+b'cde). need some help
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  2. #2
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    Re: boolean algebra simplify

    Please post questions about Boolean algebra in the Discrete Math forum. The lobby is for introductions only.

    Both answers are correct, but obviously the book answer is shorter. To show that they are equivalent, it is sufficient to show that c'+b'de = c'+b'cde. Viewed more abstractly, it is sufficient to show that x + y = x + yx' (substitute x = c' and y = b'de). Indeed,

    x + y = x + y1 = x + y(x + x') = x + yx + yx' = 1x + yx + yx' = (1 + y)x + yx' = 1x + yx' = x + yx'.
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