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Math Help - Help me solve this equation please.

  1. #1
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    Talking Help me solve this equation please.

    3^[(sqrt x) -1]+3^[2-(sqrt x)]=12
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: Help me solve this equation please.

    This forum is for introductions. The forums most appropriate for this topic is either algebra or pre-calculus.

    Anyway, I think I would rewrite the equation as follows:

    3^{\sqrt{x}-1}+3^{2-\sqrt{x}}-12=0

    Multiply through by 3^{\sqrt{x}+1}=3\cdot3^{\sqrt{x}}:

    \left(3^{\sqrt{x}} \right)^2-36\left(3^{\sqrt{x}} \right)+27=0

    Now you have a quadratic in 3^{\sqrt{x}.
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  3. #3
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    Re: Help me solve this equation please.

    \displaystyle a^{m-n} = \frac{a^m}{a^n}

    Does this make life easier?
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  4. #4
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    Re: Help me solve this equation please.

    [3^(sqrtx)]/3 + 3^2/3(sqrtx)=12?
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  5. #5
    MHF Contributor
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    Re: Help me solve this equation please.

    some advice ... look at post #2 again
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