3^[(sqrt x) -1]+3^[2-(sqrt x)]=12
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3^[(sqrt x) -1]+3^[2-(sqrt x)]=12
This forum is for introductions. The forums most appropriate for this topic is either algebra or pre-calculus.
Anyway, I think I would rewrite the equation as follows:
Multiply through by:
Now you have a quadratic in.
Does this make life easier?
[3^(sqrtx)]/3 + 3^2/3(sqrtx)=12?
some advice ... look at post #2 again