# Suman Thapa

• Nov 13th 2012, 07:21 AM
sumanthapa
Suman Thapa
I need a help to solve the question regarding normal distribution. The question is :
If X and Y are standard normal distribution and are independent then how to find the pdf and mgf of XY?
• Nov 13th 2012, 08:17 AM
abender
Re: Suman Thapa
The (univariate) normal PDF is given by $f_X(x) = \frac{1}{\sqrt{2\pi\sigma^2}}e^-{\tfrac{(x-\mu)^2} {2\sigma^2}}$.

When $X$ is standard normal, $\mu=0 \text{ and } \sigma=1$, so that the standard normal PDF is $f_X(x) = \frac{1}{\sqrt{2\pi}}e^{-{\tfrac{x^2} {2}}}$.

$Y$ is also a standard normal random variable, so its PDF is similarly $f_Y(y) = \frac{1}{\sqrt{2\pi}}e^{-{\tfrac{y^2} {2}}}$.

Now, If $X$ and $Y$ are INDEPENDENT, then $f_X(x) \cdot f_Y(y) = f_{X,Y}(x,y)$.

So, $f_{X,Y}(x,y) = f_X(x) f_Y(y) = \left(\frac{1}{\sqrt{2\pi}}e^{-{\tfrac{x^2} {2}}}\right)\left(\frac{1}{\sqrt{2\pi}}e^{-{\tfrac{y^2} {2}}}\right) = \frac{1}{2\pi}e^{-{\tfrac{x^2+y^2} {2}}}$.
• Nov 13th 2012, 08:42 AM
sumanthapa
Re: Suman Thapa
Thanks for the solution. But I mean, if Z = XY (product of X and Y), where X and Y are standard normal distribution, then how to find the pdf and moment generating function(mgf) of Z? Could you please help me? Thanks.