problem posted here ...
how many numbers less than or equal to N with all digits unique
... for the OP: please do not double post. The lobby is for introductions.
Hi all
I am really bad at combinatorics and need some help. I have stumbled on to the problem which states that
"How many numbers upto N have all unique digits in them?"
eg - suppose N = 34. Then answer is 31 (11, 22, 33 excluded, so 34 - 3 = 31). How do I solve this for a generic case? I cant understand how to extend the idea for 3 digits and above numbers.
Any help would be appreciated. And please do explain your answer to. I would really be thankful for any help which can improve my combinatorics?
Thanks
Anant
problem posted here ...
how many numbers less than or equal to N with all digits unique
... for the OP: please do not double post. The lobby is for introductions.