# first post in this forum

• Nov 2nd 2012, 04:21 AM
VivekRFJackey501
first post in this forum
A spends 1/4 of her savings on bike and 1/3 less than she spent on the bike for a car. what fraction of her savings did she spent on bike and car?
• Nov 3rd 2012, 05:29 AM
puresoul
Re: first post in this forum
let her savings be x

She spends x/4 on bike and x/4 - 1/3 on the car.
To find how much she spent on both you add them
x/4 + x/4 -1/3 = x/2-1/3 = (3x-2)/6
• Nov 3rd 2012, 09:06 AM
Georgetown
Re: first post in this forum
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• Nov 3rd 2012, 12:28 PM
MarkFL
Re: first post in this forum
I would state the fraction $\displaystyle f$ of her savings spent as:

$\displaystyle f=\frac{1}{4}+\left(1-\frac{1}{3} \right)\cdot\frac{1}{4}=\frac{1}{4}\left(1+\frac{2 }{3} \right)=\frac{1}{4}\cdot\frac{5}{3}=?$
• Nov 3rd 2012, 01:26 PM
Deveno
Re: first post in this forum
Quote:

Originally Posted by puresoul
let her savings be x

She spends x/4 on bike and x/4 - 1/3 on the car.
To find how much she spent on both you add them
x/4 + x/4 -1/3 = x/2-1/3 = (3x-2)/6

there is an error, here.

it should be: x/4 + (x/4 - (1/3)(x/4)) = x/4 + x/4 - x/12 = 2x/4 - x/12 = 6x/12 - x/12 = (6x - x)/12 = 5x/12.

5x/12 is what fraction of x?