Answer – (A)

Solution:

The number of ways of choosing the first square is 64. The number of ways of choosing the second square is 63.

There are a total of 64*63=4032 ways of choosing two squares.

If the first square happens to be any of the four corner ones, the second square can be chosen in 2 ways.

If the first square happens to be any of the 24 squares on the side of the chess board, the second square can be chosen in 3 ways.

If the first square happens to be any of the 36 remaining squares, the second square can be chosen in 4 ways.

Hence the desired number of combinations:

=(4*2)+(24*3)+(36*4)=224

Therefore, the required probability =224

4032

= 1/18

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