how to solve 3/x+4 minus 8/x-4 =11/x^2-16
Hello, DeziB!
$\displaystyle \text{Solve for }x\!:\;\frac{3}{x+4} - \frac{8}{x-4} \:=\:\frac{11}{x^2-16}$
We are given: .$\displaystyle \frac{3}{x+4} - \frac{8}{x-4} \;=\;\frac{11}{(x-4)(x+4)}$
Multiply by $\displaystyle (x\!-\!4)(x\!+\!4)\!:\;\;3(x-4) - 8(x+4) \:=\:11$
Got it?