f(x)(=e^2)(sinx)
$\displaystyle e^2$ is just a constant ...
How do you find the first and second derivative of this function?
f(x)(=e^2)(sinx)
$\displaystyle f'(x) = e^2 \cos{x}$
$\displaystyle f''(x) = -e^2 \sin{x}$
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