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Math Help - Percentages and Fractions Help!

  1. #1
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    Percentages and Fractions Help!

    Participants in the local soccer league this year is 10% greater than it was last year. The number of males increased by 5%, and the number of females increased by 20%. What fraction of the soccer league is now female?

    I just can't seem to get this problem started....
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  2. #2
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    Re: Percentages and Fractions Help!

    m + f = number of participants last year

    1.1(m + f) = number of participants this year

    1.05m + 1.2f = also the number of participants this year

    so ... what now?
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  3. #3
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    Re: Percentages and Fractions Help!

    we substitute?

    1.05m + 1.2f = 1.1(m + f)
    then I divided
    (21/22)m + (24/22)f = m + f
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  4. #4
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    Re: Percentages and Fractions Help!

    OK, solve your last equation for m in terms of f.

    then remember what you're trying to find ... the fraction of the league that is female
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  5. #5
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    Re: Percentages and Fractions Help!

    solving for m I get:

    (1/11)f = 1/22 m
    2f = m

    Okay, so 1/3 of the participants are female.

    Holy cow, that was so simple. Ive been working on it all day...and thinking too hard about it. haha
    Thank you so much!
    Last edited by SalanderSmash; September 16th 2012 at 03:43 PM.
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