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Math Help - Fractional Algebriac Equation help!!

  1. #1
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    Fractional Algebriac Equation help!!

    Hi, when I try to solve the equation below, I come up with 36, as seen below. I multiply each term by to in order to get ride of the fractions. However, I get an answer of 36, but the answer is 72. What am I doing wrong?

    a+b+c+d = 180

    b = a/2
    c=b/2
    d=3c


    a + a/2 + (a/2)/2 + 3[(a/2)/2] = 180
    which becomes...
    a + a/2 + (a/2 * 1/2) + 3((a/2) * (1/2)) = 180
    which becomes...
    2a + a + a + 6a = 360
    which becomes...
    10a=360
    which becomes...
    a=36
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  2. #2
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    skeeter's Avatar
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    Re: Fractional Algebriac Equation help!!

    asked and answered ... do not double post

    Fractional Algebriac Equation help!!
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