asked and answered ... do not double post
Fractional Algebriac Equation help!!
Hi, when I try to solve the equation below, I come up with 36, as seen below. I multiply each term by to in order to get ride of the fractions. However, I get an answer of 36, but the answer is 72. What am I doing wrong?
a+b+c+d = 180
b = a/2
c=b/2
d=3c
a + a/2 + (a/2)/2 + 3[(a/2)/2] = 180
which becomes...
a + a/2 + (a/2 * 1/2) + 3((a/2) * (1/2)) = 180
which becomes...
2a + a + a + 6a = 360
which becomes...
10a=360
which becomes...
a=36
asked and answered ... do not double post
Fractional Algebriac Equation help!!