Does not matter how many kids a family has.
Prob(1st=boy)=.51
Prob(2nd=boy)=.51
Prob(3rd=boy)=.51
Prob(4th=boy)=.51
Prob(5th=boy)=.51
Prob(1&2&3&4&5=boy)=0.51^5=.034503
I need to know the answer and if possible the process for finding the answer to the following problem:
What is the probability that a ten child family will include 5 boys ina row?
I really would like to know what the possible number of favourable events there are and if someone can take the time - the actual combinations in a 10 child family.
Thanks for the help.