# Hi!! please need help putting formula's on graphs..

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• Sep 11th 2012, 07:13 AM
westraad
Hi!! please need help putting formula's on graphs..
Hi there!!!(Hi)

I am in need of some urgent help... if anyone would be so kind as to help me i would soooo appreciate it!! (Bow)

I'm a homeschooled missionary in Mozambique, and have exams coming up next week, and i need to understand this one problem, but i can't!! Here it is:

How do i put the formulae P=50 + 2T and P=20 + 3T on a axis graph? i have axis Y and axis X.

If i must explain any further, i so would appreciate any help!!

THANK YOU!!

Westraad
• Sep 11th 2012, 07:36 AM
emakarov
Re: Hi!! please need help putting formula's on graphs..
Quote:

Originally Posted by westraad
How do i put the formulae P=50 + 2T and P=20 + 3T on a axis graph? i have axis Y and axis X.

You should either have Y = 50 + 2X with axes Y and X or P = 50 + 2T with axes P and T. Assuming the latter, choose some values of the independent variable, i.e., T, and compute the corresponding values of the dependent variable, i.e., P. E.g., for T = 1 you get P = 50 + 2 * 1 = 50 + 2 = 52. Then plot the resulting pairs (T, P) on the graph and connect them. As it turns out, the graph of P = 50 + 2T is a straight line, so it is sufficient to find two points. Choose any T1, T2, compute P1 = 50 + 2 * T1, P2 = 50 + 2 * T2, plot (P1, T1) and (P2, T2) and connect them.
• Sep 11th 2012, 07:44 AM
Prove It
Re: Hi!! please need help putting formula's on graphs..
Quote:

Originally Posted by westraad
Hi there!!!(Hi)

I am in need of some urgent help... if anyone would be so kind as to help me i would soooo appreciate it!! (Bow)

I'm a homeschooled missionary in Mozambique, and have exams coming up next week, and i need to understand this one problem, but i can't!! Here it is:

How do i put the formulae P=50 + 2T and P=20 + 3T on a axis graph? i have axis Y and axis X.

If i must explain any further, i so would appreciate any help!!

THANK YOU!!

Westraad

Use P as your dependent variable (Y) and T as your independent variable (X). Then your first equation has a P (Y) intercept of 50 and gradient 2, and the second equation has P (Y) intercept of 20 and gradient of 3.

Does that help?
• Sep 11th 2012, 09:19 AM
westraad
Re: Hi!! please need help putting formula's on graphs..
THANK YOU SO MUCH!!!!!! (Rofl)(Rofl)(Rofl)(Rofl)(Rofl)

I figured it out! i sooo appreciate your all's help here!! (Evilgrin)
• Sep 11th 2012, 10:30 AM
HallsofIvy
Re: Hi!! please need help putting formula's on graphs..
Note that those are linear equations and lines are determined by two points. Find two (x, y) pairs satisfying each equation, plot those points, and draw a line through those points. For example if x= 0 and y= 50+ 2x, then y= 50+ 2(0)= 50 so one point is (0, 50). y= 0, the 0= 50+ 2x, 2x= -50, and x= -25. Another point is (-25, 0). Mark those points on the axes and draw the line through them.