The formula for compound interest (when computed continuously over each year) is:
Is this what you needed?
hi there could anybody solve this compound interest question with the help of log for me for me ? p=100 t=30 years A=100000 R=? given log 2= 0.3010 and log 1259=3.1 Please show me full solution http://mathhelpforum.com/images/smil...106-crying.gif