How to use the method of substitution to solve the following simultaneous equation?
3x+10y=51
x-y/2=11/2
What are the following steps?
Determine y in the 2nd equation:
$\displaystyle x-\frac y2=\frac{11}2~\implies~\boxed{y=2x-11}$ [A]
Now replace y by the term 2x-11 in the 1st equation:
$\displaystyle 3x+10y=51~\implies~3x+10(2x-11)=51~\implies~23x = 161~\implies~x=7$
Now re-substitute the value of x into the equation [A] to get the value of y.