Thread: The problem of finding the shortest distance of the figure

I calculate the question by this formula: DH+HE+EF+FB
I found the length of DH+FB by Pyth. theorem.
Then, I got the total length of DH+FB is 16.4m
∴DH+HE+EF+FB is equal to 16.4+19+9m =44.4m
But the correct answer is C.
Is the shortest distance= DH+HE+EF+FB(m)?
Can anybody help me to solve this question? Thank you.

The shortest distance is DE+EB
Use Pythagoras Theorem to find DE+EB=SQRT(625+36)+ SQRT(225+36)=SQRT(661)+SQRT(261)
ANSWER IS 41.9

Generally speaking, the shortest distance between any two points is a straight line. If there is something blocking that straight line, then the shortest distance is the closest you can get to this blockage to go around it. So I agree with Hemvanezi, the shortest distance is DE + EB. Alternatively, you could do DG + GB.