Find the integral of {{(x^{4} + 1)^{1/2} }[ ln( x^{2} + 1 ) + 2lnx]} /x^{4}
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Originally Posted by sohamjariwala Find the integral of {{(x^{4} + 1)^{1/2} }[ ln( x^{2} + 1 ) + 2lnx]} /x^{4} It doesn't have a closed form solution. Maybe try a series solution instead...
I think I made a mistake in writing it the correct question is {{x^{2 }+ 1)^{1/2}[ ln(x^{2} + 1) - 2lnx]}/x^{4}
Last edited by sohamjariwala; Jul 12th 2012 at 10:41 PM.
integral[Sqrt[x^2 + 1]*(Log[x^2 + 1] - 2*Log[x] )/(x^4)] - Wolfram|Alpha Unfortunately it's not showing the steps...
Superb,My friend thank you.
I also have another problem. Can you figure out what to substitute. Integrate w.r.t. x 1/[(cot(x/2)cot(x/3)cot(x/6)]
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