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Math Help - 'as an average'

  1. #1
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    'as an average'

    Hi everyone, it's been a very long time since i have done any maths. Could someone please show me how to work out this problem.

    If an event occurs 6 times in 18 months, what is the average weekly occurance?

    Thanks.

    Blue
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  2. #2
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    Re: 'as an average'

    one time in twelve weeks
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  3. #3
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    Re: 'as an average'

    Quote Originally Posted by Bluemoon View Post
    Hi everyone, it's been a very long time since i have done any maths. Could someone please show me how to work out this problem.

    If an event occurs 6 times in 18 months, what is the average weekly occurance?

    Thanks.

    Blue
    18 months = 1.5 years= 78 weeks So 6 times in 78 weeks = 6/78 times in 1 week That is 1/13 times per week
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  4. #4
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    Re: 'as an average'

    thanks but I want to learn how to work it out
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  5. #5
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    Re: 'as an average'

    Biff I'm good upto 6/78 then not sure how to get to 1/13
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  6. #6
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    Re: 'as an average'

    Quote Originally Posted by Bluemoon View Post
    Biff I'm good upto 6/78 then not sure how to get to 1/13
    13 x 6 = 78, so you can cancel the factors of 6 in the numerator and the denominator.
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  7. #7
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    Re: 'as an average'

    Thank you very much, learning has taken place!
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