'as an average'

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• Jun 7th 2012, 10:53 PM
Bluemoon
'as an average'
Hi everyone, it's been a very long time since i have done any maths. Could someone please show me how to work out this problem.

If an event occurs 6 times in 18 months, what is the average weekly occurance?

Thanks.

Blue
• Jun 7th 2012, 11:10 PM
sanjaykanojia
Re: 'as an average'
one time in twelve weeks
• Jun 8th 2012, 12:11 AM
biffboy
Re: 'as an average'
Quote:

Originally Posted by Bluemoon
Hi everyone, it's been a very long time since i have done any maths. Could someone please show me how to work out this problem.

If an event occurs 6 times in 18 months, what is the average weekly occurance?

Thanks.

Blue

18 months = 1.5 years= 78 weeks So 6 times in 78 weeks = 6/78 times in 1 week That is 1/13 times per week
• Jun 8th 2012, 04:52 AM
Bluemoon
Re: 'as an average'
thanks but I want to learn how to work it out
• Jun 8th 2012, 04:53 AM
Bluemoon
Re: 'as an average'
Biff I'm good upto 6/78 then not sure how to get to 1/13
• Jun 8th 2012, 04:55 AM
Prove It
Re: 'as an average'
Quote:

Originally Posted by Bluemoon
Biff I'm good upto 6/78 then not sure how to get to 1/13

13 x 6 = 78, so you can cancel the factors of 6 in the numerator and the denominator.
• Jun 8th 2012, 04:59 AM
Bluemoon
Re: 'as an average'
Thank you very much, learning has taken place!