a number which sum of digit is 1977. Prove that the number will not be a perfect square

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- Jun 1st 2012, 09:42 AMSwarnavNumber theory problems
a number which sum of digit is 1977. Prove that the number will not be a perfect square

- Jun 1st 2012, 12:45 PMSorobanRe: Number theory problems
Hello, Swarnav!

Quote:

A number whose sum of digits is 1977.

Prove that the number will not be a perfect square.

Note: in this problem, a "number" means a positive integer.

Consider the*digital*__root__

Add the digits together.

If the sum has more than one digit, add its digits together.

Continue until we have a one-digit sum.

That is the digital root of the number.

A number can have only nine possible digital roots.

Examine the digital roots of their squares.

. . $\displaystyle \begin{array}{ccc}\text{digit root} && \text{digital root} \\ \text{of }n & n^2 & \text{of }n^2 \\ \hline 1 & 1 & 1 \\ 2 & 4 & 4 \\ 3 & 9 & 9 \\ 4 & 16 & 7 \\ 5 & 25 & 7 \\ 6 & 36 & 9 \\ 7 & 49 & 4 \\ 8 & 64 & 1 \\ 9 & 81 & 9 \end{array}$

The digital root of a square must be: $\displaystyle 1, 4, 7,\text{ or }9.$

Since the digital root of $\displaystyle 1977$ is $\displaystyle 6$, it can__not__be a square.

- Jun 2nd 2012, 04:45 AMSwarnavRe: Number theory problems
but 6660 is not a perfect square, but it digit sum is 6+6+6+0=18,then 1+8=9.

- Jun 2nd 2012, 11:21 AMSorobanRe: Number theory problems
Hello, Swarnav!

Quote:

But 6660 is not a perfect square, but it digit sum is 6 + 6 + 6 + 0 = 18, then 1 + 8 = 9.

Read my post again . . .

I said:**If**a number is a square,**then**its digital root is 1, 4, 7 or 9.

You are taking the converse:

. . "**If**a number's digital root is 1, 4, 7 or 9,**then**it must be a square."

I didn't say that.

We cannot trust the converse.

Consider the true statement: "If the figure is a square, then it has four side."

The converse is: "If the figure has four sides, then it is a square."

This statement may or may not be true . . . agreed?

- Jun 2nd 2012, 10:59 PMSwarnavRe: Number theory problems
yes,i have understood. thanks. but please can you help me to find a general form for all valid numbers?