1. ## University Maths question

Can anyone help me out with this badboy?

Find a method for converting a repeating expansion (with any period
t and any numbers of non-repeating digits between the point and the rst repeating digit) from binary tohexadecimal, without converting to base ten at any stage. Then convert the repeating binaryexpansion
10101.001101 (the last 5 digits 01101 are repeating)
to hexadecimal (without using base ten). [Note the one non-repeating digit before the re-
peating part.]

2. ## Re: University Maths question

Hello, lucasterry!

Find a method for converting a repeating decimal expansion (with any period and any number of non-repeating digits
between the decimal point and the 1st repeating digit) from binary to hexadecimal, without converting to base ten.
Then convert the repeating binary expansion $10101.0\overline{01101}$ to hexadecimal (without using base ten).

To convert $11101001011100.011_2$ to hexadecimal, group the digits is sets of four,
. . starting at the decimal point and reading to the left and right.

We have: . $11|1010|0101|1100|.0110|$

Convert each group to hexadecimal: . $\underbrace{11}_3|\underbrace{1010}_{10}| \underbrace{0101}_5|\underbrace{1100}_{12}|. \underbrace{0101}_6|$

Therefore: . $3A5C.6_{16}$

We are given: . $10101.0\overline{01101}_2$

We have: . $\underbrace{1}_1|\underbrace{0101}_5|.\underbrace{ 0011}_3|\underbrace{0101}_5|\underbrace{1010}_{10} |\underbrace{1101}_{13}|\underbrace{0110}_6| \underbrace{1011}_{11}|\underbrace{0101}_5| \underbrace{1010}_{10}|\underbrace{1101}_{13}| \hdots$

Therefore: . $15.3\,\overline{5AD6B}_{16}$