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Math Help - Geometry experts, only (please).

  1. #1
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    Geometry experts, only (please).

    Greetings. I need a geometry expert, please.

    I have an 8 inch, 390 degree, chimney pipe coming into my basement at a 45 degree angle. I need to cut out a tin heat shield that lays flat against the wall, around the pipe. Obviously, it would be "eliptical-ish" (my word), but I wonder what the equation for this would be?

    Thanks very much
    Dave Vanwerkhoven
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  2. #2
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    Re: Geometry experts, only (please).

    I don't understand question
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  3. #3
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    Re: Geometry experts, only (please).

    Quote Originally Posted by Vanwerkhoven View Post
    Greetings. I need a geometry expert, please.

    I have an 8 inch, 390 degree, chimney pipe coming into my basement at a 45 degree angle. I need to cut out a tin heat shield that lays flat against the wall, around the pipe. Obviously, it would be "eliptical-ish" (my word), but I wonder what the equation for this would be?

    Thanks very much
    Dave Vanwerkhoven
    1. Draw a sketch (see attachment)

    2. I assume that the 8' are refferring to the diameter? The minor axis has then the length b = 4. The major axis has consequently the length

    a = \frac{4}{\cos(45^\circ)}=4 \cdot \sqrt{2}

    3. The equation of the ellipse is:

    \frac{x^2}{32} + \frac{y^2}{16} = 1
    Attached Thumbnails Attached Thumbnails Geometry experts, only (please).-ebener_zylinderschnitt.png  
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