Thread: trig question

need help with these questions -

solve sin(2x-45) = √ 3 / 2

and

find general solutions of sin2x=cosx

thankyou in advance

Originally Posted by jshine96

need help with these questions -

solve sin(2x-45) = √ 3 / 2

and

find general solutions of sin2x=cosx

thankyou in advance

Go from here.





Go from here.

Originally Posted by jshine96

need help with these questions -

solve sin(2x-45) = √ 3 / 2

and

find general solutions of sin2x=cosx

thankyou in advance

next time, please post trig questions in the trig forum.

sorry, i forgot to add -

solve sin(2x-45) = √ 3 / 2 for -180 ≤ x ≤ 180

Originally Posted by jshine96

sorry, i forgot to add -

solve sin(2x-45) = √ 3 / 2 for -180 ≤ x ≤ 180

It's solved in exactly the same way, you just let n be whatever values will give you solutions in the given domain.

sorry.. i still don't get how to solve it :L [i get the first part]

and for this question find general solutions of sin2x=cosx

i understand what you wrote, but confused on what to do next.. do I solve what x is? like 90, 27, 30, 150?