need help with these questions - solve sin(2x-45) = √ 3 / 2 and find general solutions of sin2x=cosx thankyou in advance
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Originally Posted by jshine96 need help with these questions - solve sin(2x-45) = √ 3 / 2 and find general solutions of sin2x=cosx thankyou in advance Go from here. Go from here.
Originally Posted by jshine96 need help with these questions - solve sin(2x-45) = √ 3 / 2 and find general solutions of sin2x=cosx thankyou in advance next time, please post trig questions in the trig forum.
sorry, i forgot to add - solve sin(2x-45) = √ 3 / 2 for -180 ≤ x ≤ 180
Originally Posted by jshine96 sorry, i forgot to add - solve sin(2x-45) = √ 3 / 2 for -180 ≤ x ≤ 180 It's solved in exactly the same way, you just let n be whatever values will give you solutions in the given domain.
sorry.. i still don't get how to solve it :L [i get the first part]
and for this question find general solutions of sin2x=cosx i understand what you wrote, but confused on what to do next.. do I solve what x is? like 90, 27, 30, 150?
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