Can anyone please help me on below math problem?
Question: A mowed 3/4 of his lawn in 5/4 hours. B, who works twice as fast, then started the remaining work and finished it. How many minutes did B work?
A ... 3/4 of the lawn in 5/4 hours = 3/4 of the lawn in 75 minutes = 1/4 of the lawn in 25 minutesQuestion: A mowed 3/4 of his lawn in 5/4 hours. B, who works twice as fast, then started the remaining work and finished it. How many minutes did B work?
1/4 of the lawn is left for B who works twice as fast ... B takes 12.5 minutes to finish
next time post problems like this in the pre-university algebra forum ... the "math talk" discussion forum is for general discussion of mathematics (no problems)