1. ## Fundamental Unitary System

Question: A mowed 3/4 of his lawn in 5/4 hours. B, who works twice as fast, then started the remaining work and finished it. How many minutes did B work?

2. ## Re: Fundamental Unitary System

Originally Posted by Mushfique

Question: A mowed 3/4 of his lawn in 5/4 hours. B, who works twice as fast, then started the remaining work and finished it. How many minutes did B work?
So A worked at a rate of (3/4)/(5/4)= 3/5 "lawn per hour". B works twice as fast that, 6/5 lawn per hour. How long does it take to mow 1/4 lawn at 6/5 lawn per hour?

3. ## Re: Fundamental Unitary System

Question: A mowed 3/4 of his lawn in 5/4 hours. B, who works twice as fast, then started the remaining work and finished it. How many minutes did B work?
A ... 3/4 of the lawn in 5/4 hours = 3/4 of the lawn in 75 minutes = 1/4 of the lawn in 25 minutes

1/4 of the lawn is left for B who works twice as fast ... B takes 12.5 minutes to finish

next time post problems like this in the pre-university algebra forum ... the "math talk" discussion forum is for general discussion of mathematics (no problems)

Thanks!