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Math Help - Complex complex nos.

  1. #1
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    Complex complex nos.

    hi... there has been a question which always crosses my mind whenever i see complex numbers...
    we say..
    |x| is defined as squareroot(x^2)
    so,
    why do we not write |i| as i... (squareroot(i^2)=i)? (note that 'i' means iota)
    now u'll say that modulus function has also been defined as distance of the argument(i, in this case) from the origin..., which u say is i unit from the origin.. but why can't be the distance of a point from the origin be 'i'(iota) units ???? whats wrong with it ???

    let me frame an example here..
    u draw a graph with Y-axis scale as i unit = 3... then in reference to this graph, do we write |3|=1 (as distance from origin=1 unit) ????? the answer is a no.... then why cant we treat iota in the same way?? here also we are defining 1 unit of y-axis as 'i'....
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  2. #2
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    Re: Complex complex nos.

    Quote Originally Posted by pranjvas View Post
    hi... there has been a question which always crosses my mind whenever i see complex numbers...
    we say..
    |x| is defined as squareroot(x^2)
    so,
    why do we not write |i| as i... (squareroot(i^2)=i)? (note that 'i' means iota)
    now u'll say that modulus function has also been defined as distance of the argument(i, in this case) from the origin..., which u say is i unit from the origin.. but why can't be the distance of a point from the origin be 'i'(iota) units ???? whats wrong with it ???

    let me frame an example here..
    u draw a graph with Y-axis scale as i unit = 3... then in reference to this graph, do we write |3|=1 (as distance from origin=1 unit) ????? the answer is a no.... then why cant we treat iota in the same way?? here also we are defining 1 unit of y-axis as 'i'....
    Do not post the same question twice under any circumstances.

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  3. #3
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    Re: Complex complex nos.

    Quote Originally Posted by Plato View Post
    Do not post the same question twice under any circumstances.

    Do you understand that?
    hey.. as i m new to this site, i didn't know that..
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