Given two triangles ABC and DEF, if they have one internal angle from each triangle equal, the opposite sides of these(angles)

equal ,and the corresponding height relative to the mentioned side equal. Then they are congruent.

How do we prove it.

I would like to discuss this interesting property and the different methods to tackle this problem.

I've found out two different methods-both of them related to circumferences-that will be posted as soon

as I gather and order the information.

Please let me know if I'm in the wrong topic, it is not my intention to irritate anyone.

Any comment will be taken into account.