Euler's number, which has the property of being the base of an exponential function so that its derivative is equal to the original function.
I am doing a review on logarithms. When I reached my last question's solution I found something strange.
Question: Solve, Ln(y-1)=1+Ln(3y+2)
The solution gives:
Step 1. Ln(y-1)-Ln(3y+2)=1
Step 2. e^( Ln((y-1)/(3y+2))=e^1
The solution then goes on:
Can you tell me what's wrong here and what does e mean without an index?
Or is there something I have failed to recognise?
You actually have the correct answer, with y = -0.8996 (one minor nit to pick - in the line right after "Finally" you should have y=(1+2e)/(1-3e)=-0.8996).
The issue is that the log of a negative number is a complex number, which has a real part consisting of the log of the absoulte value of that negative number plus an imaginary part equal to pi. This comes from: log(-a) = log(-1 x a) = log (-1) + log (a), and form e^(i pi) =-1 you get log(-1) = i pi. So your solution of -0.8996 when put back into the original equation yields:
ln(y-1) = 1 + ln(3y+2)
ln(-1.8996) = 1 + ln(-0.69883)
ln(1.8996)+i pi = 1 + ln(0.69883) + i pi
0.6416 + i pi = 1 + -0.3584 + i pi
0.6416 + i pi = 0.6416 + i pi
So it checks out.
Since you are doing a problem involving "ln(x)", I presume you know what that means. It is the inverse function to " ". And that means just the number "e" to the x power. Saying that is "without an index" means it is , just as "x", in a polynomial "without a coefficient" would be "1x".what does e mean without an index?