How possible is x^2+xy+xz+z be grouped and factor out, iv been trying but there seem no
common binomial n the expression. Please guide me on this. Thank you
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when i tried to solve it it became:
x(x+y) + z(x+1) ... i could not see the common here
I don't think it factorises...
there must be something wrong with the book... it has been asked in the Activity...
Originally Posted by rcs there must be something wrong with the book... it has been asked in the Activity... Are you sure you copied it correctly? I would assume that the expression is supposed to be
Yes it can be solved when x^2 + xy +xz +yz=x(x+y)+z(x+y)
= (x+y)(x+z). algebra word problems
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