1. ## factor by grouping

How possible is x^2+xy+xz+z be grouped and factor out, iv been trying but there seem no
common binomial n the expression. Please guide me on this. Thank you

2. ## Re: factor by grouping

when i tried to solve it it became:

x(x+y) + z(x+1) ... i could not see the common here

3. ## Re: factor by grouping

I don't think it factorises...

4. ## Re: factor by grouping

there must be something wrong with the book... it has been asked in the Activity...

5. ## Re: factor by grouping

Originally Posted by rcs
there must be something wrong with the book... it has been asked in the Activity...
Are you sure you copied it correctly? I would assume that the expression is supposed to be $x^2+xy+xz+yz.$

6. ## Re: factor by grouping

Yes it can be solved when x^2 + xy +xz +yz=x(x+y)+z(x+y)
= (x+y)(x+z).

algebra word problems