How possible is x^2+xy+xz+z be grouped and factor out, iv been trying but there seem no

common binomial n the expression. Please guide me on this. Thank you

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- July 5th 2012, 07:40 PMrcsfactor by grouping
How possible is x^2+xy+xz+z be grouped and factor out, iv been trying but there seem no

common binomial n the expression. Please guide me on this. Thank you - July 6th 2012, 12:13 AMrcsRe: factor by grouping
when i tried to solve it it became:

x(x+y) + z(x+1) ... i could not see the common here - July 6th 2012, 12:41 AMProve ItRe: factor by grouping
I don't think it factorises...

- July 6th 2012, 05:52 PMrcsRe: factor by grouping
there must be something wrong with the book... it has been asked in the Activity...

- July 6th 2012, 06:56 PMReckonerRe: factor by grouping
- August 1st 2012, 03:26 AMkraj8995Re: factor by grouping
Yes it can be solved when x^2 + xy +xz +yz=x(x+y)+z(x+y)

= (x+y)(x+z).

algebra word problems