# factor by grouping

• Jul 5th 2012, 06:40 PM
rcs
factor by grouping
How possible is x^2+xy+xz+z be grouped and factor out, iv been trying but there seem no
common binomial n the expression. Please guide me on this. Thank you
• Jul 5th 2012, 11:13 PM
rcs
Re: factor by grouping
when i tried to solve it it became:

x(x+y) + z(x+1) ... i could not see the common here
• Jul 5th 2012, 11:41 PM
Prove It
Re: factor by grouping
I don't think it factorises...
• Jul 6th 2012, 04:52 PM
rcs
Re: factor by grouping
there must be something wrong with the book... it has been asked in the Activity...
• Jul 6th 2012, 05:56 PM
Reckoner
Re: factor by grouping
Quote:

Originally Posted by rcs
there must be something wrong with the book... it has been asked in the Activity...

Are you sure you copied it correctly? I would assume that the expression is supposed to be \$\displaystyle x^2+xy+xz+yz.\$
• Aug 1st 2012, 02:26 AM
kraj8995
Re: factor by grouping
Yes it can be solved when x^2 + xy +xz +yz=x(x+y)+z(x+y)
= (x+y)(x+z).

algebra word problems