# problems that I can't solve

• May 11th 2012, 11:06 AM
OPETH
problems that I can't solve
Dividend a, division, b^2, divisior c, remainder 42

a + b + c + d What value least ?

a)54 b) 53 c) 49 d)55 e) 50
• May 11th 2012, 02:25 PM
skeeter
Re: problems that I can't solve
Quote:

Originally Posted by OPETH
Dividend a, division, b^2, divisior c, remainder 42

a + b + c + d What value least ?

a)54 b) 53 c) 49 d)55 e) 50

I know what a dividend, divisor, and remainder are, however ...

any info about d ? what, exactly do you mean by "division, b^2" and what does it have to do with a and c (and d) ?

please quote the question as it was presented to you ...
• May 11th 2012, 03:05 PM
Soroban
Re: problems that I can't solve
Hello, OPETH!

We need a LOT of clarification . . .

Quote:

Dividend a, division, b^2, divisior c, remainder 42 . [1]

a + b + c + d . What value least ? . [2]

. . a) 54 . . b) 53 . . c) 49 . . d) 55 . ., e) 50

[1] A division has: dividend, divisor, quotient, and remainder.
. . .In your problem, which is which?

[2] What is d?

None of the choices are appropriate.

Since the remainder is 42, the dividend $a$ must be at least 42.
Since the remainder is 42, the divisor $c$ must be at least 43.

Already we have: . $a + c \:\ge\:85$
• May 12th 2012, 01:39 AM
OPETH
Re: problems that I can't solve
Sorry!

a, b, c are naturel numbers.

Dividend a, division $b^2
$
, divisior c, remainder 42

$a: b^2 = c
$
, remainder 42
a + b + c

Which is value least (miniumum) ?

a)54 b) 53 c) 49 d)55 e) 50
• May 12th 2012, 07:11 PM
Wilmer
Re: problems that I can't solve
Is this a cryptic puzzle?
• May 24th 2012, 04:53 PM
themathlete1
Re: problems that I can't solve
I just have a homework question I've been stuck on and hoping you guys can help me out a bit.
COnsider the number 48. If you add 1 to it, you get 49, which is a perfect square. If you add 1 to its (1/2), you get 25, which is also a perfect square. Please find the next 2 numbers with the same properties. like 48+1=49 (perfect square)
48/2=24, 24+1=25 (perfect square)

Thank you so much!