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Math Help - Polynomial story problem.

  1. #1
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    Polynomial story problem.

    Set up a polynomial equation and solve it in order to answer the question:

    A rectangular parcel of land is 50ft. wide. The length of a diagonal between opposite corners is 10ft. more than the length of the parcel. What is the parcels length?


    Any help is very much appreciated.
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  2. #2
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    Quote Originally Posted by zagsfan20 View Post
    Set up a polynomial equation and solve it in order to answer the question:

    A rectangular parcel of land is 50ft. wide. The length of a diagonal between opposite corners is 10ft. more than the length of the parcel. What is the parcels length?...
    Hello,

    a rectangle consists of two congruent right triangles. The diagonal ofthe rectangle is the hypotenuse of the right triangle.

    You can use Pythagorian rule:

    Let l be the length of the rectangle
    let d be the diagonal of the rectangle: d = l +10

    Then you get the equation:

    50^2+l^2=(l+10)^2 \ \Longleftrightarrow \ 2500+l^2=l^2+20l+100 Solve for l.

    I've got l = 120 ft.

    EB
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  3. #3
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    Hello, zagsfan20!

    Did you make a sketch?

    Set up a polynomial equation and solve it in order to answer the question.

    A rectangular parcel of land is 50 ft wide.
    The length of a diagonal is 10 ft more than the length.
    What is the parcel's length?
    Code:
          * - - - - - - - - - - - - - *
          |                       *   |
          |                   *       |
          |          L+10 *           |
          |           *               | 50
          |       *                   |
          |   *                       |
          * - - - - - - - - - - - - - *
                        L
    Then, as earboth pointed out: . (L+10)^2\:=\:L^2 + 50^2

    Go for it!
    Last edited by CaptainBlack; January 12th 2007 at 08:02 AM.
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