Thread: Mixture problem

Q) A mixture of 125 galllons of wine and water contains 20% of water.How much water must be added to the mixture in order to increase the percentage of the water to 25% of the new mixture?

Thanks

Originally Posted by a69356

Q) A mixture of 125 galllons of wine and water contains 20% of water.How much water must be added to the mixture in order to increase the percentage of the water to 25% of the new mixture?

Thanks

1. The actual mixture contains gallons of water.

2. Let x denote the additional water then you know:



3. Solve for x.

Spoiler:

I've got

Hello, a69356!

A mixture of 125 galllons of wine and water contains 20% water.
How much water must be added to increase the percentage of the water to 25%?

When I first learned "Mixture Problems", I made a chart . . .


The chart has the formula across the top:
. .

. .


We start with 125 gallons of mixture which is 20% water.
. . We have: . gallons of water.
Write this in the first row:

. .


We add gallons of water (which is 100% water).
. . We add: . gallons of water.
Write this in the second row.

. .


The final mixture has gallons which is 25% water.
. . It contains: . gallons of water.
Write this in the third row.

. .


Read down the last column.

We start with 25 gallons of water, then add gallons of water.
. . Hence, the mixture contains gallons of water. [1]


Read across the last row.

We have gallons which is 25% water.
. . Hence, the mixture contains gallons of water. [2]


We just described the final amount of water in two ways.

There is our equation!

Got it?