If ak = 1/k-1/(k+1), then find out the summation of a2 to a100?
(Here k, 2 & 100 are suffixes)
a2=3
a3=2
a4=5/3 and so on i dont see any pattern how to find the summation ,is there any direct formula
i cant understand
1/(k-1)/(k+1) lets put k=2 now this yields 1/(2-1)/(2+1)=1/3 which is not equal to (2+1)/(2-1)=3 i still cant understand how both the fractions r equal now if we take 1/k-1/(k+1) = 1/2-1/(3)=(3-2)/6 which is equal t0 1/6 now this both r not equal how u say all fractions are equal ..