this is kind of a follow on from my previous post.
= c(2^{n + 1} - 1)
What I don't understand is how we get from the 3rd step to the 4th. If n is 5 then it will take 31 moves, which is what we have up to the 3rd step. Then the is 32 alone. What am i missing?
thanks.
not sure i qute understand this part
if c is part of the summation then if then meaning i'm one move short. But the c is not part of the summation then there is no c in the summation. Am I missing something again?
Ignore this, just realised that raised to 0 is equal to 1.