solve the equation

(2^x)(3^(x+1)=10

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- Jul 18th 2009, 02:07 AMRose WanjohiLogarithm
solve the equation

(2^x)(3^(x+1)=10 - Jul 18th 2009, 02:13 AMe^(i*pi)
- Jul 18th 2009, 02:24 AMRose Wanjohilogarithm
yeah i got it,

xlog2+xlog3+log3=1

log3=0.4771

log2=0.3010

therefore 0.3010x+0.4771x+0.4771=1