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Math Help - Friction

  1. #1
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    Friction

    The skid mark left on the road by a vehicle which had its wheels locked is 120 m . The coefficient of kinetic friction between the road and the tyres is 0.75 . Assuming that the kinetic energy of the vehicle equals the work done against friction , derive the relationship between the speed , v of the vehicle before the wheels aRe locked and the length L of the skid mark on the road .
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  2. #2
    Super Member malaygoel's Avatar
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    Quote Originally Posted by thereddevils View Post
    The skid mark left on the road by a vehicle which had its wheels locked is 120 m . The coefficient of kinetic friction between the road and the tyres is 0.75 . Assuming that the kinetic energy of the vehicle equals the work done against friction , derive the relationship between the speed , v of the vehicle before the wheels aRe locked and the length L of the skid mark on the road .
    Kinetic energy dissipated= work done by friction

    Kinetic energy dissipated= \frac{1}{2}mv^2
    where m is the mass of the vehicle, and it is assumed that the vehicle stops after skid.

    Work done by friction= \mu mgL
    where \mu=0.75(given, coefficient of friction), g is acc. due to gravity.
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