I was on this question for over 45 minutes and I was stumped! I really have no idea what to do! Please help!
The diagram above shows a pillar (lying horizontally) made of two uniform sections X and Y each of cross-sectional area . The sections are made from two different materials. The weights of X and Y are shown in the diagram acting through the centre of gravity of each section.
The pillar will balance horizontally when supported vertically below point P.
Show, using the principle of moments, the the point P is 1.2m from the end of the pillar (the right side of section Y).
Take the right end of the pillar to be x=0 m, then the centre of mass of the
first segmant is at x=0.4 m, and the second is at x=1.4 m. Thus for balance
about P we need:
and I make the solution of this P=1.12 m.
Is that, "the moment of a force about a point is the product of the force and its perpendicular distance from the point"?
Or is that, "in a system in static equilibrium, the summation of moments about a point is zero"? Or, clockwise moments equal counterclockwise moments, so no movement?
Here is one way of solving your problem here.
In the figure, if the beam will balance horizontally if supported vertically below point P, then P is vertically in line with the centroid of the beam. So, the total weight of the beam can be imagined as concentrated at, or vertically with, point P.
So, the external force, F, to balance the beam vertically below point P is
F = Resultant of downward forces = 1000 +250 = 1250 N.
Summation of moments about the lower righthand corner of the composite figure is zero.
Let x = horizontal distance of point P, and so of force F=1250N, from the lower righthand corner, in meter.
Clockwise moment is negative; counterclockwise moment is positive.
[250(0.8 /2)] -[1250(x)] +[1000(0.8 +(1.2 /2))] = 0
100 -1250x +1400 = 0
x = -1500 / (-1250)
x = 1.2 m --------------------answer.