Originally Posted by
shadow6 Mary is playing golf. The diagram below describes her situation. Determine the equation of this relation. Then find the time when the ball is 20m away from the hole.
What I did so far was the following:
Find a using P(0, 15) and s = -50, t = 50 into y=a(x-s)(x-t).
15 = a(0-(-50))(0-50)
15 = a(50)(-50)
15 = 2500a
3/500 = a
Therefore the equation of this relation is y = 3/500(x+50)(x-50)
Now the problem is, I'm not sure how to find the time. Do I substitute 20m into the above equation? Also, what units would the time be in?