Thread: Ellipse problem with "a" and "b" parameters

1. Ellipse problem with "a" and "b" parameters

I don't know about other countries but in mine, the rule of an ellipse is:

((x-h)^2)/a^2 + ((y-k)^2)/b^2 = 1

I determined the (h,k) to be (4,-6) which is right but how do I determine the proper a and b values?

Any help would be greatly appreciated!

2. Originally Posted by s3a
I don't know about other countries but in mine, the rule of an ellipse is:

((x-h)^2)/a^2 + ((y-k)^2)/b^2 = 1

I determined the (h,k) to be (4,-6) which is right but how do I determine the proper a and b values?

Any help would be greatly appreciated!
dont know for that rule...
never heard of it.

Anyway the rules for anything in math are the same everywhere.

ellipse formula is:

( x/a )^2 + ( y/b )^2 = 1

and the right answer is B) because you have ( 4, -3 ) , ( 4, -9 ) // ( x, y )

if you put x = 4 in B) you will get y1 = -3, y2 = -9

3. Originally Posted by s3a
...

...how do I determine the proper a and b values?...

!
Typically a and b are the major and minor diameters of the ellipse.