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Math Help - projectile motion

  1. #1
    MHF Contributor
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    projectile motion

    A bomb is released from a plane which is diving at an angle of 30 degrees from the vertical . The plane is at a height of 1000m when the bomb is released . The bomb hits the ground 10s later . What is the speed of the plane when the bomb is released .

    My attempt :

    s=ut+\frac{1}{2}at^2

    1000=usin30(10)+frac{1}{2}(9.81)(10)^2

     <br />
u= 101.9 mms^{-1}<br />

    But it is wrong .. Wonder where my mistake is .. THanks for helping me out .
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by mathaddict View Post
    A bomb is released from a plane which is diving at an angle of 30 degrees from the vertical . The plane is at a height of 1000m when the bomb is released . The bomb hits the ground 10s later . What is the speed of the plane when the bomb is released .

    My attempt :

    s=ut+\frac{1}{2}at^2

    1000=usin30(10)+frac{1}{2}(9.81)(10)^2

     <br />
u= 101.9 mms^{-1}<br />

    But it is wrong .. Wonder where my mistake is .. THanks for helping me out .
    Diving 30 degrees from the vertical = diving 60 degrees from the horizontal.

    Initial downward velocity component is v sin(60) m/s not v sin(30) m/s, where v is the plane's speed at weapon release.

    CB
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