A bomb is released from a plane which is diving at an angle of 30 degrees from the vertical . The plane is at a height of 1000m when the bomb is released . The bomb hits the ground 10s later . What is the speed of the plane when the bomb is released .
My attempt :
But it is wrong .. Wonder where my mistake is .. THanks for helping me out .
Diving 30 degrees from the vertical = diving 60 degrees from the horizontal.
Originally Posted by mathaddict
Initial downward velocity component is v sin(60) m/s not v sin(30) m/s, where v is the plane's speed at weapon release.