Inverse function

**Curious_eager** · May 30th 2009, 03:33 AM

Find the inverse of the function:

f(t) = (10^t - 10^(-t))/(10^t + 10 ^ (-t))

Thanks,
Anshu

**earboth** · May 30th 2009, 04:48 AM

Originally Posted by Curious_eager

Find the inverse of the function:

f(t) = (10^t - 10^(-t))/(10^t + 10 ^ (-t))

Thanks,
Anshu

$f(t)=y=\dfrac{10^t-\dfrac1{10^t}}{10^t+\dfrac1{10^t}} = \dfrac{10^{2t}-1}{10^{2t}+1}$

Solve the equation for t:

$y= \dfrac{10^{2t}-1}{10^{2t}+1}$ Substitute $a = 10^{2t}$

$y= \dfrac{a-1}{a+1}~\implies~a=\dfrac{y+1}{y-1}$

Now re-substitute:

$10^{2t}=\dfrac{y+1}{y-1}~\implies~2t=\log\left(\dfrac{y+1}{y-1}\right)~\implies~\boxed{t=\dfrac12\cdot \log\left(\dfrac{y+1}{y-1}\right)}$

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