# :(---Rational Exponents---:(PLZ HELP

• Sep 15th 2005, 03:46 PM
Anti-Math
:(---Rational Exponents---:(PLZ HELP
^=exponent
X=multiply
x=variable

4^(-2)
4^(-3)-4^(0)

Solve for x:
3^(2x+1-x+2)=3^(x2-x)

Anyone know how to solve these??? :confused:
• Sep 15th 2005, 07:27 PM
MathGuru
Remember that x^(-1) = 1/x
Also remember that x^0 = 1

so 4^(-3) = 1/(4^3)

And

4^(-2)
4^(-3)-4^(0)

can be rewritten as

1/16
1/64-1

can you take it from there?
• Sep 15th 2005, 07:29 PM
MathGuru
3^(2x+1-x+2)=3^(x2-x)

take log_3 of both sides to render the equation

2x+1-x+2 = x2-x, did you mean x^2 instead of x2 anyway you can take it from here I'm sure.
• Sep 15th 2005, 07:32 PM
MathGuru
Learn Latex, you will love it
BTW we usually use * for multiply to avoid confusion with the variable x

you can also learn latex and write stuff like this $\frac{1}{3 \cdot x^{-2}}$

click on it to find out what I did.
• Sep 16th 2005, 02:46 PM
Anti-Math
Thnx