Given any real number, x, there exist a real number, called "-x" such that x+ (-x)= 0. (If x= 0, then -x= 0 also. For any other x, -x is not equal to x).
There is no number that, added to infinity gives 0. No, is NOT equal to 0!
Another is "if x is a real number, then x+ 1> x. That is not true for x= infinity.
No. That is wrong.
Suppose for the sake of contradiction that,
add 1 to both sides:
Then Rules 1a and 1c:
Then using a rule you yourself agreed with, , leaves us with:
Giving
This is similar to what opalg said, which was pretty much the only piece of evidence needed to refute what you are saying.
It's all very well asking questions and pushing ideas, that's what this site is for and that's why I love it, but when people who really do know what they are talking about are throwing counterproof after counterproof at you, I think it's time to step back and assess the situation.
Read around the subject, read what has been suggested untill you fully understand it. If there is then something you struggle to understand, ask for help. When help is given to you on good authority, do not dismiss it with shoddy maths, try instead to use it to better your understanding.