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Thread: graphing

  1. #1
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    graphing

    If the graphs of $\displaystyle x + 3y 5 = 0$ and $\displaystyle px + 2y +1 = 0$ are to meet at right angles, then the value of $\displaystyle p $ is:

    -6, 6, $\displaystyle 2/3$, -$\displaystyle 2/3$ or -$\displaystyle 3/2$ ?
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  2. #2
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    Quote Originally Posted by foreverbrokenpromises View Post
    If the graphs of $\displaystyle x + 3y 5 = 0$ and $\displaystyle px + 2y +1 = 0$ are to meet at right angles, then the value of $\displaystyle p $ is:

    -6, 6, $\displaystyle 2/3$, -$\displaystyle 2/3$ or -$\displaystyle 3/2$ ?
    your first eqn is $\displaystyle x+3y-5=0$ ?

    its slope $\displaystyle = \frac{-1}{3}$

    slope of second line $\displaystyle =\frac{-p}{2}$

    if the two lines are perpendicular then their slopes will be negative reciprocal of each other.

    $\displaystyle \frac{-1}{3}=\frac{2}{p}$

    $\displaystyle p=-6$
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