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Thread: graphing

  1. May 24th 2009, 06:03 PM #1
    foreverbrokenpromises
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    graphing

    If the graphs of x + 3y – 5 = 0 and px + 2y +1 = 0 are to meet at right angles, then the value of p is:

    -6, 6, 2/3, - 2/3 or - 3/2 ?
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  2. May 24th 2009, 06:23 PM #2
    Shyam
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    Quote Originally Posted by foreverbrokenpromises View Post
    If the graphs of x + 3y – 5 = 0 and px + 2y +1 = 0 are to meet at right angles, then the value of p is:

    -6, 6, 2/3, - 2/3 or - 3/2 ?
    your first eqn is x+3y-5=0 ?

    its slope = \frac{-1}{3}

    slope of second line =\frac{-p}{2}

    if the two lines are perpendicular then their slopes will be negative reciprocal of each other.

    \frac{-1}{3}=\frac{2}{p}

    p=-6
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