Results 1 to 2 of 2

Math Help - Graphing

  1. #1
    Junior Member
    Joined
    May 2009
    Posts
    68

    Graphing

    The original graphy, y=f(x) is transformed into a new graph y=4 f(2x-2)-3 using progression. If the point (4, -11) is on the transformed graph, then a point guranteed to be on the original graph is :
    a) 3, -1
    b) 6, -16
    c) 4, -2
    d) 6, -2
    e)1, -2

    my teacher gave me a package of 50 questions and didnt explain to us how to do the questions. he just told us to do them
    so i am very confused right now!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    12,135
    Thanks
    1013
    Quote Originally Posted by foreverbrokenpromises View Post
    The original graphy, y=f(x) is transformed into a new graph y=4 f(2x-2)-3 using progression. If the point (4, -11) is on the transformed graph, then a point guranteed to be on the original graph is :
    a) 3, -1
    b) 6, -16
    c) 4, -2
    d) 6, -2
    e)1, -2

    my teacher gave me a package of 50 questions and didnt explain to us how to do the questions. he just told us to do them
    so i am very confused right now!
    y = 4 \cdot f(2x-2) - 3

    sub in the values from the given point for the transformation ... x = 4 , y = -11

    -11 = 4 \cdot f(2(4) - 2) - 3

    simplify ...

    -2 = f(6)
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. graphing
    Posted in the Algebra Forum
    Replies: 6
    Last Post: May 19th 2011, 06:43 AM
  2. graphing
    Posted in the Math Topics Forum
    Replies: 1
    Last Post: May 24th 2009, 07:23 PM
  3. graphing of sin and cos
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: October 28th 2008, 10:50 AM
  4. Graphing
    Posted in the Trigonometry Forum
    Replies: 3
    Last Post: January 16th 2008, 12:18 PM
  5. help with graphing
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: December 9th 2007, 10:23 AM

Search Tags


/mathhelpforum @mathhelpforum