Thread: Specific Gravity

Hello,

How do I calculate the following specific gravity.

Chemical A = SG of 1.2
Water = SG 1

I add 11 litres of water to 5 litres of Chemical A which gives me approx 4.84% solution

Now - I do not have a hydrometer - so is there a formula to calculate the Specific Gravity of the final solution.

All clues will be appreciated

Hello Cliff

Originally Posted by Cliff

Hello,

How do I calculate the following specific gravity.

Chemical A = SG of 1.2
Water = SG 1

I add 11 litres of water to 5 litres of Chemical A which gives me approx 4.84% solution

Now - I do not have a hydrometer - so is there a formula to calculate the Specific Gravity of the final solution.

All clues will be appreciated

Welcome to Math Help Forum!

Sorry if this answer comes rather late.

The specific gravity of chemical A is 1.2 means it's 1.2 times as dense as water; in other words, if you have equal volumes of water and chemical A, the mass of chemical A is 1.2 times the mass of the water. A litre of water has a mass of 1 kg, so if you mix 11 litres of water and 5 litres of chemical A, the total mass is

$\displaystyle 11 + 5\times 1.2 = 17$ kg.

And the volume is $\displaystyle 11 + 5 = 16$ litres.

So the specific gravity of the mixture is $\displaystyle \frac{17}{16}= 1.0625$

I hope that helps.

Grandad

Many thanks