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Math Help - mechanics (vectors)

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    mechanics (vectors)

    A particle P moves in a horizontal plane. The acceleration of P is (i + 2j) m s2. At time t = 0, the velocity of P is (2i 3j) m s1.

    (a) Find, to the nearest degree, the angle between the vector j and the direction of motion of P when t = 0.
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    Quote Originally Posted by Aquafina View Post
    A particle P moves in a horizontal plane. The acceleration of P is (i + 2j) m s2. At time t = 0, the velocity of P is (2i 3j) m s1.

    (a) Find, to the nearest degree, the angle between the vector j and the direction of motion of P when t = 0.
    direction of motion is \theta = \arctan\left(-\frac{3}{2}\right) = -56.3 degrees relative to the vector i

    so ... relative to the vector j , it would be ... what?
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