Hi, I am finding it difficult to undertake this question, can anyone please assist me?

Find dy/dx in terms of x and y for:

x^2 = arctan(y) / 1+y^2

Any help much appreciated,

Dranalion.

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- Apr 26th 2009, 12:31 AMDranalionCalculus, dervatives
Hi, I am finding it difficult to undertake this question, can anyone please assist me?

Find dy/dx in terms of x and y for:

x^2 = arctan(y) / 1+y^2

Any help much appreciated,

Dranalion. - Apr 26th 2009, 02:33 AMHallsofIvy
- Apr 26th 2009, 03:42 AMDranalion
I got this however, what have I done?

(1+y^2)*x^2 = arctan(y)

2x(1+y^2) + x^2(1+2yy') = y'/(1+y^2)

2x+2xy^2+x^2+2yy'x^2 = y'/(1+y^2)

2x+2xy^2+x^2 = y'/(1+y^2) - 2yy'x^2 = y'(1/(1+y^2) - 2yx^2)

y' = (2x+2xy^2+x^2) / (1/(1+y^2) - 2yx^2) - Apr 26th 2009, 03:48 AMSoroban
Hello, Dranalion!

Quote:

Find for: .

And might as well get rid of the product . . .

Differentiate: .

. .

Factor: .

- Apr 26th 2009, 04:18 AMkangaroo
I got